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eduard
3 years ago
14

Find mHK. pls hurry and answer lol

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

mHK= 104

Step-by-step explanation:

X+39=4X

39 = 3x

X=13

13+39=4(13)

52=52

HK=52+52

mHK=104

Rashid [163]3 years ago
7 0
It would be mark N? I think
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After eliminating radicals, what quadratic equation can you solve to find the potential solutions of sqrt 2x+3 - sqrt x+1 = 1
aniked [119]

Answer:

Step-by-step explanation:

We have given:

√2x+3 - √x+1  = 1

First of all isolate the square root of the left hand side:

√2x+3 = √x+1 +1

Now take square on both sides.

(√2x+3)^2 = (√x+1 +1)^2

Open the R.H.S by squaring formula.

∴(a+b)^2 = a^2+2ab+b^2

2x+3 = (√x+1)^2 + 2(√x+1)(1)+(1)^2

2x+3 = x+1 +2√x+1 +1

2x+3 = x+2 +2√x+1

Combine the like terms:

2x-x+3-2 = 2√x+1

x+1 = 2√x+1

Take square on both sides

(x+1)^2 = (2√x+1)^2

x²+2x+1 = 4x+4

x²+2x-4x+1-4 = 0

x²-2x-3 = 0

Now solve the quadratic equation:

a = 1 , b= -2 , c = -3

x = -b+/-√b²-4ac/2a

x = -(-2)+/-√(-2)² - 4(1)(-3) / 2(1)

x = 2 +/- √4+12 / 2

x = 2+/- √16/2

x = 2+/- 4 /2

x = 2+4/2     , x = 2-4/2

x = 6/2      , x = -2/2

x = 3      , x = -1

The solutions we get is (3, -1).

3 0
3 years ago
Read 2 more answers
I really need help. And its setted up-
Contact [7]

Answer:

4: 300

5: 95

have a good day :]

8 0
3 years ago
A. 3<br> B. 1/3<br> C. -3<br> D. -1/3
guapka [62]

Answer:

D

Step-by-step explanation:

This is a negative slope since it is going from left to right so that leaves you with c or d.

The slope is rise over run so in this case the rise is 1 and the run is -3 since its going left.

This leads you to -1/3

Hope this helped :)

5 0
3 years ago
Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

so, we will find partial derivatives

f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



7 0
3 years ago
Read 2 more answers
Pls answer! Dylan spots an airplane on radar that is currently approaching in a straight line, and
anastassius [24]

Answer:

13510 ft

Step-by-step explanation:

I have attached a triangle diagram to depict this situation.

From the diagram, we see that distance between A and B is denoted by x.

Now, from trigonometric ratios in this type of triangle, let's first find y.

6400/y = tan 36

y = 6400/tan 36

y = 8808.84 ft

Now, we can find x from;

6400/(8808.84 + x) = tan 16

6400/tan 16 = 8808.84 + x

22319.452 = 8808.84 + x

x = 22319.452 - 8808.84

x ≈ 13510 ft

5 0
3 years ago
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