Answer:
28.0
Step-by-step explanation:
if rounding to the nearest tenth then the number in the hundredth determines what to do - if the number in hundredths is '5 and above, give it a shove'
meaning in this case the 7 bumps the 9 up by one; but a nine will carry over and bump the number in the ones place up by one
Answer:
see explanation
Step-by-step explanation:
Expressing as equations
9x + 10y = 297 → (1) ← that is B
8x + 5y = 194 → (2) ← that is D
To solve the system of equations, multiply (2) by - 2
- 16x - 10y = - 388 → (3)
Add (1) and (3) term by term to eliminate the term in y
(9x - 16x) + (10y - 10y) = (297 - 388), that is
- 7x = - 91 ( divide both sides by - 7 )
x = 13
Substitute x = 13 into either of the 2 equations and solve for y
Using (1), then
(9 × 13) + 10y = 297
117 + 10y = 297 ( subtract 117 from both sides )
10y = 280 ( divide both sides by 10 )
y = 28
Cost of a small box of candy = $13
Cost of a large box of candy = $28
F(3) = 5 [5-3=2 diff]
f(4) = 8 [8-4=4 diff] (or 2 times larger than f(3)’s diff)
If that holds true, then continue the pattern:
f(5) = 13 [2 times f(4) diff = 8 so 5 + 8 = 13]
f(6) = 22
f(7) = 39
f(8) = 72
The only problem with my answer is that it could be times 2 or ^2. My answer above assumes times 2.
Answer:
![\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=-\log 4](https://tex.z-dn.net/?f=%5Clog%202-%5Clog%208%3D%5Clog%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%5Clog%202-%5Clog%208%3D-%5Clog%204)
Step-by-step explanation:
![\log 2-\log 8=\log\frac{2}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=\log\frac{1}{4}\\\\\log 2-\log 8=\log 1-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \log\frac{a}{b}=\log a-\log b\\\\\log 2-\log 8=-\log 4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \log 1=0](https://tex.z-dn.net/?f=%5Clog%202-%5Clog%208%3D%5Clog%5Cfrac%7B2%7D%7B8%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Clog%5Cfrac%7Ba%7D%7Bb%7D%3D%5Clog%20a-%5Clog%20b%5C%5C%5C%5C%5Clog%202-%5Clog%208%3D%5Clog%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%5Clog%202-%5Clog%208%3D%5Clog%201-%5Clog%204%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Clog%5Cfrac%7Ba%7D%7Bb%7D%3D%5Clog%20a-%5Clog%20b%5C%5C%5C%5C%5Clog%202-%5Clog%208%3D-%5Clog%204%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Clog%201%3D0)
Answer:
![\boxed{ \bold{ \huge{ \boxed{ \sf{( - 2.5 \: , \: - 0.5)}}}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%20%5Chuge%7B%20%5Cboxed%7B%20%5Csf%7B%28%20-%202.5%20%5C%3A%20%2C%20%5C%3A%20%20-%200.5%29%7D%7D%7D%7D%7D)
Step-by-step explanation:
Let the given points be A and B
Let A( -8 , 5 ) be ( x₁ , y₁ ) and B ( 3 , -6 ) be ( x₂, y₂ )
<u>Finding</u><u> </u><u>the</u><u> </u><u>midpoint</u>
![\boxed{ \sf{midpoint = (\frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%7Bmidpoint%20%3D%20%20%28%5Cfrac%7Bx1%20%2B%20x2%7D%7B2%7D%20%2C%20%5C%3A%20%20%5Cfrac%7By1%20%2B%20y2%7D%7B2%7D%20%29%7D%7D)
![\dashrightarrow{ \sf{( \frac{ - 8 + 3}{2} , \: \frac{5 + ( - 6)}{2} )}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%28%20%5Cfrac%7B%20-%208%20%2B%203%7D%7B2%7D%20%2C%20%5C%3A%20%20%5Cfrac%7B5%20%2B%20%28%20-%206%29%7D%7B2%7D%20%29%7D%7D)
![\dashrightarrow{ \sf{( \frac{ - 8 + 3}{2} \: , \: \frac{5 - 6}{2} )}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%28%20%5Cfrac%7B%20-%208%20%2B%203%7D%7B2%7D%20%20%5C%3A%20%2C%20%5C%3A%20%20%5Cfrac%7B5%20-%206%7D%7B2%7D%20%29%7D%7D)
![\dashrightarrow{ \sf{( \frac{ - 5}{2} \: , \: \frac{ - 1}{2} )}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%28%20%5Cfrac%7B%20-%205%7D%7B2%7D%20%20%5C%3A%20%2C%20%5C%3A%20%20%5Cfrac%7B%20-%201%7D%7B2%7D%20%29%7D%7D)
![\dashrightarrow{ \sf{( - 2.5 \: , \: - 0.5 \: )}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%28%20-%202.5%20%5C%3A%20%2C%20%5C%3A%20%20-%200.5%20%5C%3A%20%29%7D%7D)
Hope I helped !
Best regards!