Question

At a pizza shop, 80% of the customers order a pizza, 15% of the customers

Answer 1

90% out of 105% which would be 0.85

Answer 2

Answer: 0.85

Step-by-step explanation:

Let A be the event that the customer orders a pizza and B be the event that the customer orders a salad.

Then , we have $P(A)=80\%=0.80$

$P(B)=15\%=0.15$

$P(A\cap B)=10\%=0.10$

Now, the probability that he or she  orders either a pizza or a salad is given by :-

$P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow\ P(A\cup B)=0.80+0.15-0.10=0.85$

Hence, the required probability = 0.85