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Fiesta28 [93]
3 years ago
7

Solve(x+y)^2=(x^2-2xy+y^2) and show your work

Mathematics
2 answers:
svp [43]3 years ago
8 0

The answer is 0!

Hope i helped :)

Shtirlitz [24]3 years ago
7 0

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

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2 years ago
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Step-by-step explanation:

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Why Did the Piano Player Bang Her
Sedbober [7]

The circumference of a circle that was computed when the diameter is 3cm will be 9.426cm.

<h3>How to find the circumference?</h3>

The circumference of a circle of gotten by the formula:

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3 0
2 years ago
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Nat2105 [25]

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By theorem of intersecting chords and tangent of a circle,

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3 years ago
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Romashka [77]

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(4) -1.

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6 0
3 years ago
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