A regular pentagon has a perimeter of 5x+15 what is the length of one side

A laundry basket contains socks in several different colors. black 70 white 26 red 4 What is the probability that a randomly sel

Gnom [1K]

Answer:

70/100

Step-by-step explanation:

You have 70 White socks

You have to add 70, 26, and 4.

When you add those, you get 100, making the answer 70/100

4 0

3 years ago

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Pls help plsssssssssssssssssssssssssssssssssss

lozanna [386]

Answer:

i belive its 1

Step-by-step explanation:

Because its SUM so its adding and the sum is 22 and 20+2=22.

6 0

3 years ago

find the domain of y equals 4 multiplied by the square root of the quantity 4 multiplied by x plus 2 end of quantity. a. x is gr

Bingel [31]

$y=4\sqrt{4(x+2)}\\\\D:4(x+2)\geq 0\ \ \ |divide\ both\ sides\ by\ 4\\\\x+2\geq0\ \ \ |subtract\ 2\ from\ both\ sides\\\\\boxed{x\geq-2}\to\boxed{c.}$

7 0

3 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

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Isolate a variable in each system. You may need to use the distributive property to simplify the equation. Show your work.

expeople1 [14]

Answer:

1. x=-7/3 + 4y/3

2. x= 6- 3y/4

Step-by-step explanation:

to isolate the variable you simply solve for it by moving all the terms which don't contain x to the right by multiplying, subtracting, adding, and dividing

5 0

3 years ago