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KIM [24]
3 years ago
8

Z-score is a transformed raw score that is forced to fit a scale where the mean is 0 and the standard deviation is 1. z-scores a

nd the normal distribution (percentages association with each standard deviation of the normal distribution). what are the values that represent the 68%, 95% (approximate and exact), and 99% (approximate and exact) ranges?
Mathematics
1 answer:
Monica [59]3 years ago
4 0
 how u dont know this stuff shhhhh on yo ahh boi
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Points If a person invests $250 at 9% annual interest, find the approximate value of the investment at the end of 15 years.
AfilCa [17]

Principal Amount = P = $250

Interest Rate = r = 9% = 0.09

Time in years = t = 15 years

Value of investment = A = ?

The formula to calculate the value on investment as a result of annual interest is:

A=P(1+r)^{t}

Using the values in the above formula, we get:

A=250(1+0.09)^{15}\\ \\  A=\$ 910.62

Thus, at the end of 15 years the value of the investment will be $ 910.62.

7 0
3 years ago
A plant has an initial height of 2 inches and grows at a constant rate of 2 inches each month. A second plant that also grows at
Alik [6]

Answer:

Answer:4.8 monthsStep-by-step explanation:First, let's write down the information that we are given.Plant A: Initial Height: 3 in.Constant Rate of Growth (CRG): 2in/month (2 inches per month)Plant B:Initial Height: 1 in.CRG: 29in/year (29 inches per year)We can see that Plant B grows 29 inches per year, so lets convert Plant B's 'CGR' to months.Plant B - Divide by 12 (12 months in a year)29/12 in/yearNow, Lets put these into equations:Plant A: y = 2x + 3Plant B: y = 29/12 x + 1Now, set these two equations together and solve for x.2x + 3 = 29/12 x + 12 = 5/12 x4.8So, after 4.8 months, the plants will be the same height.

hope it helps you

6 0
3 years ago
Paula drinks 1 tenth gallon of milk every morning. How many days will it take Paula to drink 1 gallon of milk,no files just type
elixir [45]

Answer:

10 days

Step-by-step explanation:

Divide 1 gallon by

0.1 gallon per day:

 1 gallon

---------------------- = 10 days

0.1 gallon/day

3 0
3 years ago
Find the volume of the cone. Round your answer to the nearest tenth.<br> 8 m<br> 8 m
Alexxandr [17]

Answer: your answer is 536.2 hope it helps

Step-by-step explanation:

6 0
3 years ago
The displacement of a particle from a reference point at any instant is given by s = 3 t 2 - 4 t + 5 , where s is in metres and
lina2011 [118]

The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t

Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

To learn more about this, tap on the link below:
brainly.com/question/2234298

#SPJ9

3 0
1 year ago
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