The amount of rim needed for each window is 141.4 in
<h3>How to find the length of the outer rim?</h3>
Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.
<h3>What is an arc?</h3>
An arc is part of section of the circumference of a circle
<h3>What is the length of an arc?</h3>
So, length of arc, L = Ф/360 × 2πR where
- Ф = central angle of arc and
- R = radius of circle.
Gven that for the window rim
- Ф = angle of the rim = 270° and
- R = radius of the rim = 30 in
Substituting the values of the variables into the equation for L, we have
L = Ф/360 × 2πR
L = 270°/360° × 2π × 30 in
L = 3/4 × 2π × 30 in
L = 3/2 × π × 30 in
L = 3 × π × 15 in
L = 45π in
L = 141.37 in
L ≅ 141.4 in
So, the amount of rim needed for each window is 141.4 in
Learn more about length of an arc here:
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We use the formula a^2 - b^2 = ( a - b )( a + b );
We have a = 5m - 2 and b = 3m - 4;
<span>(5m-2)^2-(3m-4)^2 = (5m - 2 -3m + 4) x (5m-2 + 3m - 4) = (2m + 2)(8m - 6) = 2(m +1) x 2(4m - 3) = 4(m+1)(4m-3);
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By greater if you mean faster, then you are comparing the fractions 11/10 and 7/6. Finding a common denominator, which is thirty, we get the fractions 33/30 and 35/30. We can see that 35>33, making Song B faster.
Answer:
$5599.20
Step-by-step explanation:
The quarterly interest rate for the first two years was ...
7%/4 = 0.0175
So, the multiplier each quarter for those 8 quarters was 1+0.0175 = 1.0175. At the end of the first 8 quarters, the account value had been multiplied by ...
1.0175^8
For the next 8 quarters, the quarterly interest rate was 10%/4 = 0.025. So at the end of those 8 quarters, the balance had been multiplied by ...
1.025^8
Then the balance at the end of 4 years was ...
$4000(1.0175^8)(1.025^8) ≈ $5599.20
The balance was $5599.20.
Answer:
96 sq yards
Step-by-step explanation:
40-24 is 16, and 16/2 is 8. 8 is the second length, so 8 times 12 is 96 which is the area
