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I am Lyosha [343]
3 years ago
7

Please awnser questions, no links, no I dont know

Mathematics
2 answers:
Lynna [10]3 years ago
8 0

Answer:

you can make 6 portions

Step-by-step explanation:

you divide 3/4(0.75) into 1/8(0.125) gives you 6

Goshia [24]3 years ago
6 0

Answer:

i,m stupied lol

Step-by-step explanation:

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Please help i need an A
Basile [38]

Answer:

(1) 820

(2) 1920

Step-by-step explanation:

(1) solving 20 x 41, using associative property.

20 * 41  = (2 x 10) x 41  = 2 x (10 x 41)

             = 20 x 41         = 2 x 410

             = 820              =  820

(2) distribute 32 as 30 + 2 and solve.

     60 x 32

  = 60 x (30 + 2) = 60(30) + 60(2)

                        = 1800 + 120

                        = 1920

             

3 0
3 years ago
At a certain store, the taco sauce was on sale for 1/5 off. With a coupon for an additional 40 cents off, the final cost of the
Karo-lina-s [1.5K]
B) c - 1/5c - 40 = 120


c- (original cost) - 1/5c (sale) - 40(coupon)= 120(final cost)

Hope that helps! :)
7 0
4 years ago
Which equation represents Grant's path?<br> y = 2 - 4x<br> y = 4-<br> y = 8 - 2x
Norma-Jean [14]
Y = 8 - 2x



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7 0
4 years ago
Read 2 more answers
In the diagram of circle A, what is m∠LMN?
vagabundo [1.1K]

we know that

The measurement of <u>the external angle</u> is the semi-difference of the arcs which includes

so

m∠LMN=\frac{1}{2}(270\°-90\°)=90\°

therefore

the answer is 90\°

3 0
3 years ago
Read 2 more answers
Every quadrilateral with opposite angles supplementary can be inscribed in a circle.TrueFalseIf a triangle is inscribed in a cir
solniwko [45]

Explanation

The Inscribed Quadrilateral Theorem states that a quadrilateral can be inscribed in a circle if and only if the opposite angles of the quadrilateral are supplementary

Answer 1: True

Also, Given a triangle, the circumscribed circle is the circle that passes through all three vertices of the triangle. The center of the circumscribed circle is the circumcenter of the triangle, the point where the perpendicular bisectors of the sides meet.

Answer 2: True

7 0
2 years ago
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