I'll do the first one to get you started
So we have g(f(x)) which means that we start with g(x) and replace the 'x' with 'f(x)' to get g(f(x))
g(x) = ( x - 4 )/2
g(f(x)) = ( f(x) - 4)/2 .... replace every x with f(x)
g(f(x)) = (2x+4-4)/2 .... replace f(x) on the right side with 2x+4
g(f(x)) = (2x+0)/2
g(f(x)) = (2x)/2
g(f(x)) = 1x/1
g(f(x)) = 1x
g(f(x)) = x
Let me know if you need help with the other one.
the top number is the exponent, the bottom number is the root.
15) ![\sqrt[3]{(2p)^{1} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282p%29%5E%7B1%7D%20%7D)
= ![\sqrt[3]{2p}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2p%7D)
16) ![16\sqrt[4]{(x)^{3} }](https://tex.z-dn.net/?f=16%5Csqrt%5B4%5D%7B%28x%29%5E%7B3%7D%20%7D)
= ![16\sqrt[4]{x^{3} }](https://tex.z-dn.net/?f=16%5Csqrt%5B4%5D%7Bx%5E%7B3%7D%20%7D)
A linear function is a function with the form f(x) = ax' + b. It looks like a regular linear equation, but instead of using y, the linear function notation is f(x). To solve a linear function, you would be given the value of f(x) and be asked to find x.
1 -since everything includes 4a, we can factor that to get 4a(a-4b^3+2b^2c)
2 - since 5 and 3 add to 8 and multiply to 15, we can do (n+5)(n+3)
3 - since -5 and -4 add to -9 and multiply to 20, we can do (g-5)(g-4)
4 - since -10 and 3 add to -7 and multiply to 30, we can do (z-10)(z+3)
5 - we can factor out 4y to get 4y(y^2-9).
I got the numbers in 2, 3, and 4 with a guesstimating and checking approach
