All categories

2 years ago

A used book store also started selling used CDs and videos. In the first week, the store sold a combin

Mathematics

1 answer:

avanturin [10]2 years ago

3 0

Answer:

300 cds

Step-by-step explanation:

because 60x3=180 and 40 divied by 4 is 10.

You might be interested in

????‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎

tatiyna

Answer:

1 and 3

Step-by-step explanation:

Part a: 1 and 3

part b: x = −22

Please mark as brainliest

Have a great day, be safe and healthy

Thank u

8 0

3 years ago

Read 2 more answers

Covert 3.92 into a mixed number in simplest form?

12345 [234]

3.92

= 1.00 + 1.00 + 1.00 + 0.92

= 100/100 + 100/100 + 100/100 + 92/100

= 300/100 + 92/100

= 392/100

-------------------------------------------------------

392/100 = 196/50 = 98/25

3 0

3 years ago

Read 2 more answers

Brandon solved 24 math problems in 8 minutes, and Marcus solved 18 math problems in 9 minutes. Who solved more problems per minu

Delicious77 [7]

Answer

Brandon

Step-by-step explanation:

Brandon solved three a minute while Marcus solved two a minute

4 0

3 years ago

Divide 25/1658 To find the quotient, start by dividing _ into _.

ololo11 [35]

Answer:

To find the quotient, you must start by dividing 25 into 1,658.

Step-by-step explanation:

6 0

3 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago