The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N
<h3>How to find the Tension in Suspended Cables?</h3>
Resolving forces in the y direction gives us;
T₁ sin 29° + T₂ sin 53° = 210 ------(eq 1)
Resolving forces in the horizontal direction gives;
T₁ cos 29° = T₂ cos 53° ----(eq 2)
T₁ = T₂ cos 53°/cos 29°
Thus;
(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210
0.3336T₂ + 0.7986T₂ = 210
T₂ = 210/1.1322
T₂ = 185.48 N
Thus;
T₁ = 185.48 cos 53°/cos 29°
T₁ = 127.63 N
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The standard deviation is proportional to the scale factor. Cutting each score in half will result in a standard deviation of
σ = 8/2 = 4
Step-by-step explanation:
Any positive number can. be a side length. It cannot pass 7 because a square with 49 sqr lnches as a area has side lengths with the measures of 7.
You would need to come in 583.6 or 584 times
