The total cost of the least expensive fence would be $800.
To minimize perimeter and maximize area we take factors that are as close to equal as possible.  In this case, the closest whole number factors are 200 and 100.  Since the north and south faces cost less, we will make those 100 ft and make the more expensive east and west faces 200 ft.
100 ft × $2/ft = $200 per side × 2 sides = $400 for the north and south facing sides.
200 ft × $1/ft = $200 per side × 2 sides = $400 for the east and west facing sides
$400 + $400 = $800
        
             
        
        
        
Answer:
no
Step-by-step explanation:
To determine if (1, 6) is a solution, substitute x = 1, y = 6 into the left side of both equations and if the value obtained equals the right side then it is a solution.
10(1) - 6 = 10 - 6 = 4 ≠ - 6
- 10(1) + 5(6) = - 10 + 30 = 20 ≠ 30
Then (1, 6 ) is not a solution to the system
 
        
             
        
        
        
Answer:
 the answer is C: 1932 sq. cm
Step-by-step explanation:
You want to break down the sections (which is double for each)
there are 6 rectangles but you will only need to calculate for 3
1st rectangle
a = (25) (12)
a = 300 sq. cm
**then multiply by 2 = 600 sq. cm**
2nd rectangle
a = (12) (18)
a = 216 sq. cm
then 216 * 2 = 432 sq. cm
3rd rectangle
a = (25) (18)
a = 450 sq. cm
then 450 * 2 = 900 sq. cm
Total Surface Area
SA = 600 sq. cm + 432 sq. cm + 900 sq. cm
SA = 1932 sq. cm
 
        
             
        
        
        
Put 16 where n is, then do the arithmetic.
... a(16) = -6 + 3(16 -1)
... a(16) = -6 + 45
... a(16) = 39
 
        
                    
             
        
        
        
Answer:
30 m 
Step-by-step explanation:
51-21=30
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