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lawyer [7]
3 years ago
8

Ben starts walking along a path at 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the sam

e path at 5 mi/h. How long (in hours) will it be before Amanda catches up to Ben?
Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

2 hours 15 minutes

Step-by-step explanation:

Given that :

Ben's speed = 3 mi/hr

One and half hours after Ben leaves = 1.5 hours

Ben's distance = 3 mi/hr * 1.5 = 4.5 miles

Amanda's speed = 5 mi/hr

Time taken before Amanda catches up:

Let time taken = x

Distance = speed * time

Ben's distance = Amanda's distance

4.5 mi + (3 * x) = 5 * x

4.5 + 3x = 5x

4.5 = 5x - 3x

4.5 = 2x

x = 4.5 / 2

x = 2.25 hours

Time taken = 2.25 * 60 = 135 minutes = 2 hours 15 minutes

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George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
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The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
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