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Ghella [55]
1 year ago
11

Edith’s age is 1/4 of Ronald’s age. In how many years will Edith’s age be 1/3 of Ronald’s age if Edith is 20 years old?

Mathematics
1 answer:
ruslelena [56]1 year ago
7 0

Answer:

10

Step-by-step explanation:

x = Edith's age = 20 years

y = Ronald's age

x = 20 = y/4

y = 20×4 = 80 years

in z years we have

(x + z) = (y + z)/3

(20 + z) = (80 + z)/3

3(20 + z) = 80 + z

60 + 3z = 80 + z

60 + 2z = 80

2z = 20

z = 10

in 10 years Edith's age will be 1/3 of Ronald's age.

then Edith will be 30, and Ronald will be 90.

30 = 90/3

correct.

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we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

so


we have

a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50

b) for x=2 y=1--------> y/x=1/2-------> 0.50

c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50

d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50

the value of k is equal to 0.50

so

<span>the relationship forms a direct variation. </span>

the equation is

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Verify

for x=1

y=0.50*(1)------> y=0.50-----> is correct


for x=2

y=0.50*(2)------> y=1.00-----> is correct


for x=3

y=0.50*(3)------> y=1.50-----> is correct


for x=5

y=0.50*(5)------> y=2.50-----> is correct

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