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lina2011 [118]
3 years ago
14

Ratios and rates are ways to relate different quantities. For example, for every 1 car, there are 4 tires. This is a ratio. What

other examples of ratios can you think of?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Step-by-step explanation:

Ratios are also used to express relationships between  part to a

whole In this problem, we are expected to sight more examples of ratios.

other examples of ratios are

1. the ratio of boys to girls in a class

 for every 1 boy, there are 3 girls

 1:3

2. the ratio of cats to dogs in a house

   say for every 2 cats there are 5 dogs

   2:5

We can go on and on, as the list of examples can be endless, the basic idea is we can relate part to part as in these examples given or a part to a whole using ratios.

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It is 1/2 mile from a student's home to a store and back. In a week, she
worty [1.4K]

Answer:

2 miles

Step-by-step explanation:

Given that :

Distance from home to store and back = 1/2 mile

In a week :

Number of times he walked from home to store and back = 1 time

Number of times she rode to store and back = 3 time

Note distance does not change whether she rode or walked:

Hence,

miles walked = 1/2 miles * 1 = 1/2 miles

Miles biked = 1/2 miles * 3 = 3/2 miles

Total Number of miles :

(1/2 + 3/2) = (1 + 3) /2 = 4/2 = 2 miles

4 0
3 years ago
Help me please o(* ̄▽ ̄*)ブ(づ ̄ 3 ̄)づ
evablogger [386]

Answer:

a) 24

b) Bowtown and Dovebury

c) 57

3 0
3 years ago
A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
V125BC [204]

We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

(the first equality is Bayes' theorem)

b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

4 0
3 years ago
Which equations are related equations to x + 8 = 22?
andre [41]

Answer:

x=22+8 and x+22=8nd 8=22_x

8 0
3 years ago
Read 2 more answers
Richard is $15 overdrawn on his checking account. He writes a check for $7. What is the balance in his checking account now?​
Annette [7]
Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
5 0
3 years ago
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