3 years ago

HELPPP Solve the equation log (2x-3)=2

Mathematics

1 answer:

MaRussiya [10]3 years ago

8 0

Answer:

2.5 or 5/2

Step-by-step explanation:

2x-3=2

2x=5 (both sides plus 3)

x=5/2 or 2.5(divid by 2 on both sides)

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What is the value of y−5x−3for x = 2 and y = -4

arlik [135]

Answer

-17

<u>Explanation</u>

y−5x−3 for x = 2 and y = -4

We solve this question by substituting the values of y and x.

y−5x−3 = -4 - 5(2) - 3

= -4 - 10 -3

= -14 - 3

= -17

8 0

3 years ago

Read 2 more answers

Zoey needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer for 3

solmaris [256]

X = Amount paid one hour
205.25 - 59 = 146.25
3.25x = 146.25
x = 146.25 ÷ 3.25

x= 45

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2 years ago

<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%203%20%3D%205" id="TexFormula1" title="2x^{2} + 3 = 5" alt="2x^{2} + 3 = 5"

sveta [45]

Answer:

x = 1

Step-by-step explanation:

2x^2 + 3 = 5
2x^2 = 5 - 3
2x^2 = 2
x^2 = 2/2
x = \| 1
x = 1

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3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

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2 years ago

What is the value of the digit 7 in 870,541

faust18 [17]

The value of 7 in 870,541 is 10,000

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3 years ago