9514 1404 393
Answer:
Step-by-step explanation:
10 years ago, the sum of their ages was 65 -2·10 = 45.
If Karl was twice as old as Eddie, his contribution was 2/3 of the sum and Eddie's was 1/3. That is, Karl was (2/3)(45) = 30 and Eddie was 15 at that time.
Now, Karl is 40 and Eddie is 25.
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This can be solved using a system of equations.
e = 65 -k
(k -10) = 2(e -10)
Substituting the first equation into the second gives ...
k -10 = 2((65 -k) -10)
k -10 = 110 -2k . . . . . . . simplify
3k = 120 . . . . . . . . . . . . add 10+2k
k = 40
e = 65 -40 = 25
that's correct, what you've put in the boxes. :)
The answer rounded to the nearest hundredth is 84.65.
Consider the number 84.647.
If we multiply this number by 1000, the result is 84647 which has 7 in its one's place.
Also, note that the value of the digit in the ones place is 4, which is half of 8, the value in the tenths place.
The remaining digit in the tenths place is 4.
Hence, the correct answer is 84.65 rounded to the nearest nundredth.
