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Kruka [31]
3 years ago
11

A rectangular painting by Leonardo da Vinci measured 62cm along its diagonal. If the painting has a height of 42 cm how wide is

the painting?
Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

{w}^{2}  +  {42}^{2}  = {62}^{2}

{w}^{2} = {62}^{2} -  {42}^{2}

{w}^{2}  = 2080

{w} =  \sqrt{2080}

w = 4 \sqrt{130}

The width of the painting is 45.6cm to the nearest tenth.

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