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4 years ago

Which of the binomials below is a factor of this trinomial?

2 answers:

6 0

Lets set our x's apart first, the 5 can only be multiplied by 1 and 5 to get it so lets put a 5 in one side and a 1 in the other... it should look like (5x )(1x )
now we have a postive in the first term and a negative in the second, this means that there will be a positive and a negative sign... now lets see what can be multiplied by 50 that can add to be 15.. lets try 25 times 2 it gives you 50 but lets check if it gives you 15 in the middle,,lets set it up like this (5x+25)(1x-2) if you multiply these will you get 5x2+15x-50?? yes you will!! so which of these factors are alike to your answer?? well the only one would be (x-2), this means your answer would be letter C

Hope this helps

____ [38]4 years ago

3 0

Answer:

x-2 is correct

Step-by-step explanation:

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What is the slope intercept equation of the line below?

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The answer is letter D

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2 years ago

A moving company charges $30 plus $0.15 Per mile to rent a moving van another company charges $15 plus $0.20 per mile to rent th

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3 years ago

Es There are 30 students on the debate team and 20 students on the math team. Ten students are on both the math team and

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There will be 40 students!!!

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3 years ago

Math help please Thanks A lot

babunello [35]

Answer:

2 hours: 3968 [I don't understand the $ sign in the answer box]

At midnight: 12137

Step-by-step explanation:

The bacteria are increasing by 15% every hour. So for every hour we will have what we started with, plus 15% more.

The "15% more" can be represented mathematically with (1 + 0.15) or 1.15. Let's call this the "growth factor" and assign it the variable b. b is (1 + percent increase).

Since this per hour, in 1 hour we'll have (3000)*(1.15) = 3450

At the end of the second hour we're increased by 15% again:

(3450)*(1.15) = 3968.

Each additional hour add another (1.15) factor, If we assign a to be the starting population, this can be represented by:

P = a(1.15)^t for this sample that increase 15% per hour. t is time, in hours.

If a represents the growth factor, and P is the total population, the general expression is

P = ab^t

Using this for a = 3000 and b = 1.15, we can find the total population at midnight after starting at 2PM. That is a 10 hour period, so t = 10

P = (3000)*(1.15)^10

P = 12137

8 0

3 years ago

The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl

Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

= 1 - 0.004

= 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is not color- blind is,

P(not CBM) = 1 - P(CBM)

= 1 - 0.004

= 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

$P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times P(\text{not CBW})\\ = 0.93 \times 0.996 \\= 0.92628\\\approx 0.9263$

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

$P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737$

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0

3 years ago