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marta [7]
3 years ago
10

Simplify -8(3y + 5) -3

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

Answer: −

2

4

−

4

3

Step-by-step explanation:

Simplify

1

Distribute

−

8

(

3

+

5

)

−

3

−

2

4

−

4

0

−

3

2

Subtract the numbers

−

2

4

−

4

0

−

3

−

2

4

−

4

3

tamaranim1 [39]3 years ago
4 0

Answer:

-24y - 43

Step-by-step explanation:

Hope this helps!

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1 and 1/6 if the man had six horses it would be one because 6 1/6'a make one
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3 years ago
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7
Sergeeva-Olga [200]

Answer:

Bank A

Step-by-step explanation:

We find the Simple Interest for each Bank

Bank A

A savings account at bank A earns 5%

simple interest.

Where

P = $5,000.00

R = 5%

T = 2 years

Compound quarterly = 4

First, convert R percent to r a decimal

r = R/100

r = 5%/100

r = 0.05 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 5,000.00(1 + 0.0125/4)(4)(2)

A = $ 5,522.43

A = P + I where

P (principal) = $ 5,000.00

I (interest) = $ 522.43

For Bank B

P = $5,000.00

R = 4%

T = 2 years

Compound quarterly = 4

First, convert R percent to r a decimal

r = R/100

r = 4%/100

r = 0.04 per year,

Then, solve our equation for A

A = P(1 + r/n)nt

A = 5,000.00(1 + 0.01/4)(4)(2)

A = $ 5,414.28

A = $ 5,414.28

A = P + I where

P (principal) = $ 5,000.00

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5 0
3 years ago
Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo
noname [10]
Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
R&({{ -1}}\quad ,&{{ 6}})\quad 
%  (c,d)
S&({{ 5}}\quad ,&{{ 5}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2}  \right)}

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it.  Well, what is the slope of RS anyway?

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -1}}\quad ,&{{ 6}})\quad 
%   (c,d)
&({{ 5}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}

and let's check the reciprocal negative of that,

\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\
slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies  +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 2}}\quad ,&{{ \frac{11}{2}}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
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% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)
\\\\\\
y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}
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Write the equation of the perpendicular bisector of MN.
nikitadnepr [17]
For this question The answer is C
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3 years ago
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yuradex [85]

Answer:

x=4/3

Step-by-step explanation:

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3 years ago
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