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3 years ago

Please help me thanks please

Mathematics

1 answer:

iragen [17]3 years ago

6 0

$\lim_{n \to \infty} a_n uuuuuuuuuuuuuuuuuuuuuuu$

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If 5x-26=x+50, then the value of x is

horsena [70]

Let's work this problem out!

First: 5(x) - 26 - x + 50 = ?

Second: 4(x) - 76 = ?

Third: 4 = ?
↑
(Solve Step 3)

Fourth: x - 19 = 0
↑
(Add the number 19 to each of your sides for Step 4)

Finally we get to your answer

19 + 0 = 19 ; 19 - 19 = 0

So, therefore the value of "x" is 19

$x = 19$

3 0

3 years ago

Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4

riadik2000 [5.3K]

<h3>The complete question:</h3>

Harold uses the binomial theorem to expand the binomial $(3x^5 -\dfrac{1}{9}y^3)^4$

(a) What is the sum in summation notation that he uses to express the expansion?

(b) Write the simplified terms of the expansion.

Answer:

(a). $(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$$

(b). $(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}$

Step-by-step explanation:

(a).

The binomial theorem says

$(x+y)^n=$$\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k $$$

For our binomial this gives

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}x^{4-k}y^k $$}$

(b).

We simplify the terms of the expansion and get:

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4$

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4$

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561} }$

3 0

3 years ago

a gym has 275 members 40% are bronze members 28% are silver members the rest are good work out the gold members

statuscvo [17]

STEP 1:
Find % of gold members. Subtract the known % of bronze and silver members from 100%.

x= percent of gold members

x= 100% - (40% +28%)
x= 100% - 68%
x= 32% percent of gold members

STEP 2:
Find number of gold members. Multiply % of gold members by the total numbers of members (275).

x= # of gold members

x= 275 * 32%
x= 275 * 0.32
x= 88 gold members

Hope this helps! :)

6 0

4 years ago

Please halpppp I’ll give brainliest if I can/ know how to!

forsale [732]

Answer:

point A = (3,9)

point D = (9,3)

point B = (6,5)

point C = (5,6)

Step-by-step explanation:

there's not really much to explain so yeah.

4 0

3 years ago

Read 2 more answers

Evaluate the expression when c=-6. c? +6c+5

artcher [175]

Answer: -31

Step-by-step explanation: 1.) Plug in -6 for c

2.) equation will then be: 6(-6)+5

3.) use PEMDAS: multiply first then addition

4.) 6(-6) equals -36

5.) add -36+5 which equal -31

Therefore your answer should be -31

8 0

3 years ago

Read 2 more answers