Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
Answer:
carbon dioxide
Explanation:
carbon dioxide is released into atmosphere
Answer:
roots spread out underground like the branches of a tree as to get sufficient water and nutrients form the soil to transport to the other parts of the tree for its own growth , by spreading out roots tend to collect or suck the maximum nutrients
Shivering
Explanation: shivering action is an act to warm a homoeothermic body. Sweating makes the body cool, panting don’t keep body warm and dilating blood vessels does not keep body warm instead constriction of blood vessels is the initial process to conserve body heat followed by waves of muscle contraction, which is nothing but shivering. Alteration of the set point in torpor is also not the right answer
