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Diano4ka-milaya [45]
2 years ago
14

Angle 5 Has what angle

Mathematics
1 answer:
Setler [38]2 years ago
8 0
The answer is B alternate exterior angle
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Help please!?!?!?! :CCC
Ksju [112]

Answer:

8.5 hope this helps sorry if its wrong :3

Step-by-step explanation:

5 0
2 years ago
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What is my current age if i am born on march 14 1993?
mafiozo [28]
Person born on March 4, 1993.

Today's Date : August 26, 2017.

Your age : 2017 - 1993 = 24.

You are 24 years old.
8 0
3 years ago
Please help me with number 5 thank you so much
ella [17]
The answer is 10 people. The way you know is because the surveyor asked the person for one answer, so if you results were 1, 0, ,10 ,7 ,13 ,2 ,9,15 ,0 and 3, then obviously only 10 people were asked because you have 10 answers.
5 0
2 years ago
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After 4 years eldi will be three times the age he had 10 years ago. Using algebra find the age of eldi
Setler [38]

Suppose that Eldi has x years old now :

x + 4 = 3 × ( x - 10 )

x + 4 = 3x - 30

Add both sides 30

x + 4 + 30 = 3x - 30 + 30

x + 34 = 3x

Subtract both sides x

x - x + 34 = 3x - x

34 = 2x

2x = 34

Divide both sides by 2

2x ÷ 2 =34 ÷ 2

x = 17

_____________________________

Thus Eldi is 17 .

3 0
3 years ago
The position vector for a particle moving on a helix is
topjm [15]

Answer:

a) 25.15

b)

   x = 1

   y = t

   z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

6 0
3 years ago
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