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Murrr4er [49]
4 years ago
15

Rewrite sin (6x) sin (x) as a sum or difference.

Mathematics
1 answer:
Ket [755]4 years ago
4 0

Recall that

\cos(x\pm y)=\cos x\cos y\mp\sin x\sin y

It follows that

\sin x\sin y=\dfrac{\cos(x-y)-\cos(x+y)}2

Replace y with 6x and you get

\sin6x\sin x=\dfrac{\cos(x-6x)-\cos(x+6x)}2=\dfrac{\cos5x-\cos7x}2

(using the fact that \cos(-5x)=\cos5x)

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6 0
3 years ago
Round 14.5 to a whole number
emmainna [20.7K]
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5 0
4 years ago
F(x)=2x+3, and g(x)=4x-2. what is f(x)+g(x)
klio [65]

Answer:

f

(

x

)

=

5

x

2

−

2

x

+

3

g

(

x

)

=

4

x

2

+

7

x

−

5

f

(

g

(

x

)

)

=

5

(

4

x

2

+

7

x

−

5

)

2

−

2

(

4

x

2

+

7

x

−

5

)

+

3

=

80

x

4

+

280

x

3

+

45

x

2

−

350

x

+

125

−

8

x

2

−

14

x

+

10

+

3

=

80

x

4

+

280

x

3

+

45

x

2

−

8

x

2

−

350

x

−

14

x

+

125

+

10

+

3

f

(

g

(

x

)

)

=

80

x

4

+

280

x

3

+

37

x

2

−

364

x

+

138

The answer is  

f

(

g

(

x

)

)

=

80

x

4

+

280

x

3

+

37

x

2

−

364

x

+

138

.

Step-by-step explanation:

8 0
3 years ago
What is the common difference of the arithmetic sequence 1/5, 6/5 , 11/5 ,16/5 , ...?
stepladder [879]
+ 5/5 each time

hope this helps
8 0
4 years ago
Read 2 more answers
What is the height of the given pyramid if the volume is 48 cubic units?
Artyom0805 [142]

The formula of a volume of a pyramid:

V=\dfrac{1}{3}Bh

B-area of a base

h-height

B=6^2=36\ u^2\\\\V=48\ u^3

Substitute:

\dfrac{1}{3}\cdot36\cdot h=48\\\\12h=48\ \ \ \ |:12\\\\\boxed{h=4\ u}

7 0
3 years ago
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