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2 years ago

Identify the slope and y-intercept of the graph of the equation.

Mathematics

2 answers:

Neko [114]2 years ago

8 0

Answer is A. 100% positive

zalisa [80]2 years ago

7 0

The slope would be 5/3 and the y-intercept would be (0,1) so the answer is A

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Tim and three friends go on holiday together for a week. The 4 friends will share the costs of the holiday equally. Here are the

castortr0y [4]

Answer: £535

Step-by-step explanation:

Herr is the complete question:

Tim and three friends go on holiday together for a week.

The 4 friends will share the costs of the holiday equally,

Here are the costs of the holiday.

£1280 for 4 return plane tickets

£640 for the villa

£220 for hire of a car for the week

Work out how much Tim has to pay for his share of the costs.

Firstly, we have to calculate the total cost of the holiday. This will be:

= £1280 + £640 + £220

= £2140

We are also told that they will share the costs equally. Since there are 4 people, Tim will have to pay:

= £2140 ÷ 4

= £535

Tim will pay £535

5 0

2 years ago

If the absolute value of x is 4, what is the value of x?

natima [27]

The absolute value of x is 4

4 0

3 years ago

Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0

3 years ago

2 mi. yd. I'm confused

dybincka [34]

Answer && Step-by-step explanation:

Obtain yards by multiplying miles by 1760

== 3520 yards

6 0

3 years ago

Find the midpoint of the line segment with end coordinates of: (-2,-2) and (2,8)

Aleonysh [2.5K]

Answer:

(0 ; 3)

Step-by-step explanation:

hello :

the midpoint of the line segment is : ((-2+2)/2 ;(-2+8)/2 )

(0 ; 3)

8 0

2 years ago

Read 2 more answers