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Alisiya [41]
2 years ago
6

Without using the formula, work out the gradient of the graph shown.

Mathematics
1 answer:
Harman [31]2 years ago
3 0

Answer:

1/3

Step-by-step explanation:

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Which function rule represents the data in the table?
likoan [24]
Y = mx + b
b: y-intercept (when x equals zero)
m: slope ((y₂ - y₁) ÷ (x₂ - x₁))

Y - Intercept:
To find the y-intercept, just look at the table. The y-intercept is whatever y equals when x equals zero. In this case it is -8.

Slope:
(y₂ - y₁) ÷ (x₂ - x₁)
Pick two points and substitute them into this equation. Let's use (-3, 1) and (-2, -2).
(-2 - 1) ÷ (-2 + 3)
-3 ÷ 1
-3

Now substitute these values back into the equation.
y = mx + b
y = -3x - 8

The answer is a.
5 0
3 years ago
The front of the stage, side C , is 50 feet long. A 40-foot rope runs along the side of square B. A 30-foot rope runs along the
vovangra [49]

Answer: yes, because any triangle with the ratio of whole number 3:4:5 is a right triangle

Step-by-step explanation:

8 0
3 years ago
A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq
alukav5142 [94]

Answer:

13, 14

Step-by-step explanation:

The parameters of the numbers are;

A whole number value = 2 × Another number + 6

The sum of the two numbers is less than 50

Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number

Where 'x' represents the second number, we get;

x + 2·x + 6 < 50

Simplifying gives;

3·x + 6 < 50

x < (50 - 6)/3 = 14.\overline 6

x < 14.\overline 6

Therefore, the numbers for which the inequality holds true are numbers less than 14.\overline 6. From the given option, the numbers are 13, and 14.

3 0
3 years ago
Which of these triangle pairs can be mapped to each other using a single reflection?​
kondor19780726 [428]

Answer:

Second triangle pair

Step-by-step explanation:

In a reflection, the shape is flipped. In the first pair, the corresponding sides as shown by the lines, and the corresponding angle are already in the same position. In the second pair, Δ MLN can be reflected so that line LN match with EG and line LM matches with line EF. ∠L and ∠E will also be mapped to each other when one triangle is reflected.

3 0
3 years ago
PLEASE HURRY!!!!!! WILL MARK BRAINLIEST TO FIRST ANSWER!!!!!!
Alika [10]

Answer:

Step-by-step explanation:

4 0
2 years ago
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