Answer:
x₁ > x₂
Step-by-step explanation:
Both actions imply a parable trajectories, since both are projectile shot cases.
Let´s call x₁ maximum distance in the first case
The maximum height is just in the middle of the curve, therefore x₁ the maximum horizontal distance is equal to 60 feet.
In the second case, the parable curve is modeled by:
y = x₂*( 0.08 - 0.002x₂) or y = 0.08*x₂ - 0.002*x₂²
A second degree equation, solving for x₂ and dismissing the value x₂ = 0
we get:
y = 0 ⇒ x₂*( 0.08 - 0.002x₂) = 0 x₂ = 0
And 0,08 - 0.002*x₂ = 0
- 0.002*x₂ = - 0.08
x₂ = 0.08/0.002
x₂ = 40 f
Then x₁ > x₂
3x+18
Step-by-step explanation:
Q^2 - 125 = 0
q^2 = 125
q = +/- sqrt 125 = 11.18, -11.18
