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Harrizon [31]
3 years ago
14

Which of the following expressions has the greatest value?

Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

2^5

Step-by-step explanation:

1^10 = 1 (1*1*1*1*1....)

5^2 = 25 (5*5)

2^5 = 32 (2*2*2*2*2)

3^3 = 27 (3*3*3)

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The angles of a triangles are x°, 3x° and 30°. When asked to solve for x, Alvi shows the work in post-it A below. Brian shows th
klasskru [66]

Answer:

See explanation

Step-by-step explanation:

OK.  Alvi is incorrect because he didn't add the measures of all 3 angles of the triangle, whereas Brian did.  So, Brian is correct and Alvi needs to work on that kind of problem.

8 0
3 years ago
Y o u s h a l l g e t 50 p o i n t s <br> i f y o u a n s w e r t h i s
Serga [27]

Answer: 1.) 10

Step-by-step explanation:

-4 + 4 = 0

0 + 6 = 6

6 + 4 = 10

6 0
3 years ago
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Someone pls help me ! i rlly need help
DerKrebs [107]

Answer:

Option D is the correct answer.

Step-by-step explanation:

Coefficients od dividend = (4, - 17, - 15)

Dividend =4x^2 - 17x - 15

Divisor x = 5 =>x-5= 0

Coefficients of Quotient = (4, 3)

Quotient =4x + 3

Remainder = 0

Since,

Dividend = Divisor \times quotient + Remainder\\\therefore 4x^2 - 17x - 15 = (x - 5)\times (4x + 3) +0 \\\therefore 4x^2 - 17x - 15 = (x - 5)\times (4x + 3) \\\therefore( 4x^2 - 17x - 15) \div (x - 5) = (4x + 3)

8 0
3 years ago
How do you answer this??
dezoksy [38]
<h3>Given</h3>
  • a rectangle x units wide and y units high divided into unit squares
<h3>Find</h3>
  • The total perimeter of the unit squares, counting each line segment once
<h3>Solution</h3>

For each of the y rows of squares, there are x segments at the top, plus another x segments at the bottom. The total number of horizontal segments is then

... horizontal segment count = (y +1)x

Likewise, for each of the x columns of squares, there are y segments to the left, plus another y segments to the right of the entire area. Then the total number of vertical segments is

... vertical segment count = (x+1)y

The total segment count is ...

... total segments = horizontal segments + vertical segments

.. = (y+1)x +(x+1)y

... total segments = 2xy +x +y

_____

<u>Check</u>

We know a square (1×1) has 4 segments surrounding it.

... count = 2·1·1 +1 +1 = 4 . . . . (correct)

We know the 3×3 window in the problem statement has 24 segments.

... count = 2·3·3 +3 +3 = 18 +3 + 3 = 24 . . . . (correct)

We know a 1×3 row of panes will have 10 frame elements.

... count = 2·1·3 +1 +3 = 6 +1 +3 = 10

It looks like our formula works well.

5 0
3 years ago
Simplify:<br> 3(9 + 2d) + 4d
Inga [223]

Answer:

27 + 10d

Step-by-step explanation:

6 0
3 years ago
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