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Bumek [7]
2 years ago
11

Diagrams A and B are scale drawing of the same field. Each square is 1 centimeter long. If the scale of diagram A is 1 cm : 24 f

t , what is the scale of diagram B?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Answer:

6cm:12cm

Step-by-step explanation:

Okay so remember this you need to know model: actual. This is really, important to know when solving.

Model: Model dimensions <u>Example: 1cm</u>

Actual: Actual dimensions <u>Example: 24ft</u>

<u></u>

Graph A:

1. Count the boxes. remember that each box is 1cm. After you counted all sides of the graph you should've gotten 12cm by 6cm.  

2. After you got your model dimensions your goal is to find the ACTUAL dimensions. By finding the actual dimensions Multiply 12(24) and 6(24) Note: you need to multiply your actual from your scale. Times your dimensions for each side.

3. After multiplying you should've got 288ft by 144ft this is your actual dimension for graph A.

Graph B:

1. Now your answer the problem is asking for also has to do with graph A. In order to do this process, you need to divide each dimension by width and length.  \frac{288}{24} this is your length \frac{144}{24} this is your width. divide

2. you should've gotten 12 and 6. now make your numbers into a scale

6cm: 12cm

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RSB [31]

Answer:

She has $20 + $0.50n in her tip jar.

Step-by-step explanation:

Amount in tip jar at noon = $20

Average amount made from each customer = $0.50

Number of additional customers served after noon = n

Therefore, we have:

Additional amount made after noon = Average amount made from each customer * Number of additional customers served after noon = $0.50 * n = $0.50n

Amount in tip jar = Amount in tip jar at noon + Additional amount made after noon = $20 + $0.50n

Therefore, she has $20 + $0.50n in her tip jar.

6 0
3 years ago
9<br> Write as a percentage.<br> 10
Ludmilka [50]

Answer:

Step-by-step explanation:

I really dont know but if I did I would say I'm a 6 grader

8 0
3 years ago
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
3 years ago
Read 2 more answers
A 30 gram sample of a substance that's used to sterilize surgical instruments has a k-value of 0.1235. Find the substances half
jok3333 [9.3K]

Answer : The substances half life in days is, 5.6 days.

Step-by-step explanation :

Half life : It is defined as the amount of time taken by a radioactive material to decay to half of its original value.

All radioactive decays follow first order kinetics.

The relation between the half-life and rate constant is:

k=\frac{0.693}{t_{1/2}}

where,

k = rate constant = 0.1235 per days

t_{1/2} = half-life

Now put all the given values in the above formula, we get:

0.1235\text {days}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=5.6\text{ days}

Thus, the substances half life in days is, 5.6 days.

5 0
3 years ago
Can you please help me solve
Digiron [165]

Answer:

First Problem:

1/2 * -2 2/5 = 1/2 * -12/5 = -12/10

Simplify -12/10 into -6/5

Step-by-step explanation:

8 0
3 years ago
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