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Bumek [7]
2 years ago
11

Diagrams A and B are scale drawing of the same field. Each square is 1 centimeter long. If the scale of diagram A is 1 cm : 24 f

t , what is the scale of diagram B?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Answer:

6cm:12cm

Step-by-step explanation:

Okay so remember this you need to know model: actual. This is really, important to know when solving.

Model: Model dimensions <u>Example: 1cm</u>

Actual: Actual dimensions <u>Example: 24ft</u>

<u></u>

Graph A:

1. Count the boxes. remember that each box is 1cm. After you counted all sides of the graph you should've gotten 12cm by 6cm.  

2. After you got your model dimensions your goal is to find the ACTUAL dimensions. By finding the actual dimensions Multiply 12(24) and 6(24) Note: you need to multiply your actual from your scale. Times your dimensions for each side.

3. After multiplying you should've got 288ft by 144ft this is your actual dimension for graph A.

Graph B:

1. Now your answer the problem is asking for also has to do with graph A. In order to do this process, you need to divide each dimension by width and length.  \frac{288}{24} this is your length \frac{144}{24} this is your width. divide

2. you should've gotten 12 and 6. now make your numbers into a scale

6cm: 12cm

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2 years ago
Math help on questions #4 and #5
Vanyuwa [196]
<h3>Answer:</h3>

4. -3

5. 3

<h3>Step-by-step explanation:</h3>

4. For x > -2, the value of a is the slope of the line. The line goes down 3 units for each 1 to the right, so the slope is -3/1 = -3. Then a = -3.

___

5. The ordered pair (h, k) is typically used to name the point to which a function is translated. The vertex of the function f(x) = |x| is (0, 0). When it is translated to (h, k), the function becomes ...

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7 0
3 years ago
Graph the numbers that are solutions to both inequalities.
nadya68 [22]

Answer:

p ∈ [5 , 6)

Step-by-step explanation:

p + 6 ≥ 11

⇒ p ≥ 11 - 6

⇒ p ≥ 5

⇒ p ∈ [5 , +∞)

3p < 18

⇒ p < 18/3

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Then

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p ∈ (-∞ , 6) ∩ [5 , +∞)

Conclusion :

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3 0
1 year ago
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