Jessica is packing her bags for her vacation. She has 9 unique Fabergé eggs, but only 3 fit in her bag.

1 answer:

3 0

The number of different groups can be found by finding 9C3 (Using combinations)
We will find combinations from n = 9 to r = 3

Therefore, 9C3 = 9!/6!*3! = (9*8*7*6!)/(6!*3*2)
= 3*4*7
= 84 ways.

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