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Tresset [83]
4 years ago
8

The graph below is an example of which type of function

Mathematics
2 answers:
docker41 [41]4 years ago
4 0

Solution:

C is the correct graph.

Explanation:

We have been given the graph and we have to tell the type of the graph.

The graph of a quadratic function is a parabola. Hence, the given graph is not the graph of quadratic function.

A linear function represents a straight line. Hence, the given graph is not the graph of linear function.

The graph of a square root function looks like a half parabola. Hence, it must not be the graph of square root function.

The end behavior of a cubic function is "opposite at both ends". We can see that the given graph meets this criteria.

Hence, the given graph represents a cubic function.

C is the correct graph.

Mrac [35]4 years ago
3 0
This equation is a cubic equation, because cubic equations are sloped and have opposite endings.
(3rd Option)
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) Complete the equations.<br> -3.<br> ?<br> = 21<br> 21 : (-3)<br> ?<br> please help
PilotLPTM [1.2K]

Answer:

-7 for both of them

Step-by-step explanation:

6 0
3 years ago
Mr. Johnson is working on constructing a square table for his classroom. He positioned his design on a coordinate grid, as shown
sasho [114]

Answer:

This is proved with the help of slope.

Step-by-step explanation:

Given Mr. Johnson is working on constructing a square table for his classroom. He positioned his design on a coordinate grid, as shown. Mr. Johnson will need to put a brace through each diagonal of the table in order to secure the table's stability.

Now, if Johnson use more than one brace then we have to prove that the braces will intersect at a right angle.

From the figure we have to prove the diagonals AC and BD are at right angle. To prove above we have to find the slopes of both diagonals.

\text{Slope of AC=}\frac{y_2-y_1}{x_2-x_1}=\frac{-5-2}{4-(-3)}=\frac{-7}{7}=-1

\text{Slope of BD=}\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-5)}{4-(-3)}=\frac{7}{7}=1

\text{Product of their slopes=}-1\times 1=-1

As we know, In a coordinate plane, the slopes of perpendicular lines are opposite reciprocals of each other i.e their product is equals to -1.

⇒ AC and BD are perpendicular

⇒ Braces which put through each diagonal intersect at right angle and the table will stable.

8 0
3 years ago
How many different passwords can be made with two letters followed by four digits (with repeat
Alexxandr [17]

Answer:

10,000 possible codes

Step-by-step explanation:

3 0
3 years ago
the circle below has center T. suppose that m UV = 138 degrees and that UW is tangent to the circle at U. find the following
alisha [4.7K]

Angle UTV is basically given: it's 138°.

Moreover, since UTV is isosceles, the other two angles have the same measure x. We thus have

138+x+x=180 \iff 2x=42 \iff x=21

So, TUV is 21°, and VUW is complementary, so it must be 69° so that they sum up to 90°

3 0
4 years ago
Write an equation of a line that passes through (-1,6) and has a slope of 4.
jeka94

Answer:

y-6=4(x+1) or y=4x+10

Step-by-step explanation:

Point: (-1,6)

m=4

Slope-point form is y-y1=m(x-x1)

y1=6

x1=-1

Now, plug it in!

y-6=4(x-(-1)) which is y-6=4(x+1)

Of course, if you want you could always simplify it down to y=4x+10 if you wanted to

Hope this helps!

7 0
3 years ago
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