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3 years ago

Can someone please help, and fast!

Mathematics

1 answer:

sleet_krkn [62]3 years ago

4 0

Answer:

-2x

Step-by-step explanation:

First you need to distribute

-2*x = -2x

-2*-5 = 10

Then set it back up

-2x + 10 - 10

Since the 10s cancel out, your final answer should be

-2x

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PolarNik [594]

Answer:

1.5

2.1/5

Step-by-step explanation:

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2 years ago

Please help thanks very much

Shalnov [3]

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3 years ago

Find the values of a,b, or c for y = x^2 - 9x +18 please help!!

kaheart [24]

Answer:

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Step-by-step explanation:

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3 years ago

How do I verify this identity? I know you should write sin2a as sin(a+a).

Kisachek [45]

SOLUTION

Given the question in the image, the following are the solution steps to verify the identity

STEP 1: Write the given identity

$\sin 2\alpha=2\sin \alpha\cos \alpha$

STEP 2: Verify the identity

$\begin{gathered} \sin 2\alpha=2\sin \alpha\cos \alpha \\ \text{Consider the left hand side of the above trigonometry identity.} \\ \text{That is, }\sin 2\alpha\text{.} \\ \text{ Rewrite }\sin 2\alpha\text{ as }\sin (\alpha+a) \\ \text{ It is known that }\sin (a+b)=\sin (a)\cos b+\cos (a)\sin (b) \\ U\sin g\text{ this statement above, we have;} \\ \sin (\alpha+a)=\sin a\cos \alpha+\cos a\sin \alpha \\ \text{It is known that }xy+yx=xy+xy=2\times xy=2xy \\ U\sin g\text{ this statement above, we have;} \\ \sin a\cos \alpha+\cos a\sin \alpha=\sin a\cos \alpha+\sin \alpha\cos \alpha=2\times\sin \alpha\cos \alpha=2\sin \alpha\cos \alpha \\ \text{Hence, }\sin 2\alpha=2\sin \alpha\cos \alpha \end{gathered}$

The verification of the identity is as seen above.

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1 year ago

Option A: 40 trash bags for $6.29 Option B: 24 trash bags for $3.89

mr Goodwill [35]

Option B is a better option.

Step by step:

I divided 40/6.29 and got about 6.3.

I divided 24/3.89 and got about 6.1.

Which is less, 6.3 or 6.1?
If you said 6.1 you are correct, so option B has a less cost, making it a better option.

8 0

2 years ago