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Vikentia [17]
3 years ago
13

HELP PLZ FIRST TO ANSWE GETS BRAINLIEST

Mathematics
1 answer:
tigry1 [53]3 years ago
7 0

Hey there!

I think the answer is B.

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nordsb [41]
40+3+.04+.003 

expanded form is showing what you have to add together


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What is 5/9 times 32?
DIA [1.3K]
5/9* 32
= (5*32)/9
= 160/9
= (153+ 7)/9
= 153/9+ 7/9
= 17+ 7/9
= 17 7/9

The final answer is 17 7/9~
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An amusement park manager determined that about 23 of all customers would wait in long lines to ride the new roller coaster. Whi
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Top Left in I.M.

Step-by-step explanation:

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3 years ago
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An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

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d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
What value should take the place of 18
rodikova [14]

Answer:

  1. the value should be twns and ones

Step-by-step explanation:

1 8=tens 8(1 ones)

3 0
3 years ago
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