To figure this out, you should think about the multiples of 10 boxes you could have.
If I had 10 small boxes, there would need to be 86 large boxes. 86 is not evenly divisible by 8 so that doesn't work.
If I had 20 small boxes, there would be 76 large boxes. 76 is not evenly divisible by 8.
If I had 30 small boxes, there would be 66 large boxes. 66 is not evenly divisible by 8.
If I had 40 small boxes, there would be 56 large boxes. 56 is every divisible by 8.
4 cartons of 10 small boxes and 7 cartons of 8 large boxes would be needed. This is a total of 11 cartons.
A) 2-5/6-4
-3/2
B) 2-0/-4-1
2/-5
C) -3- -4/-6-8
1/-14
Answer: (8y+1)(y+5)
Step by step:
8y2 + y +40y + 5
y(8y+1) + 5(8y+1)
(8y+1)(y+5)
Answer:
factorise out 7, x and y:
Answer:
solve the 3y and 2y first
Step-by-step explanation:
