Find the cosine of ∠J.

Mathematics

1 answer:

SOVA2 [1]2 years ago

6 0

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Assume that thermometer readings are normally distributed with a mean of degrees and a standard deviation of 1.00degrees C. A th

Andrew [12]

Answer:

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0 degrees

Standard Deviation, σ = 1 degrees

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(Between 0.50 degrees and 1.75 degrees)

$P(0.50 \leq x \leq 1.75)\\\\ = P(\displaystyle\frac{0.50 - 0}{1} \leq z \leq \displaystyle\frac{1.75-0}{1})\\\\ = P(0.50 \leq z \leq 1.75)\\= P(z \leq 1.75) - P(z < 0.50)\\= 0.9599 - 0.6915 = 0.2684 = 26.84\%$

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

7 0

3 years ago

Is this right please help meh

Mama L [17]

Yes you are correct very nice job!

4 0

3 years ago

Read 2 more answers

If the ratio of a circle's sector to its total area is 1/3, what is the measure of

nalin [4]

Answer:

option A: 120°

Step-by-step explanation:

$Area \ of \ circle = \pi r^2\\\\Area \ of \ sector = \pi r^2 \frac{ \theta}{360}\\\\Ratio \ of \ sector \ to \ circle = \frac{1}{3}\\\\That is, \\\frac{1}{3} = \frac{\pi r^2 \frac{\theta}{360}} {\pi r^2}\\\\\\\frac{1}{3} = \frac{\theta}{360} \\\\\frac{360}{3} = \theta\\\\120 = \theta$