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Stolb23 [73]
4 years ago
14

A greenhouse in a tri-county area has kept track of its customers for the last several years and has determined that it has abou

t 10,000 regular customers. Of those customers, 28% of them plant a vegetable garden in the spring. The greenhouse obtains a random sample of 800 of its customers. Is it safe to assume that the sampling distribution of , the sample proportion of customers that plant a vegetable garden, is approximately normal? Answer Yes or No.
Mathematics
1 answer:
Anni [7]4 years ago
7 0

Answer:

No

Step-by-step explanation:

N = 10,000

n= 800

p = .28

Sampling distribution drawn from specific population. So it is not safe to assume that sampling proportion of customers is approximately normal.

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Answer:

a)1 cup of flour

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Step-by-step explanation:

a) A recipe requires 3 cups of flour to make 27 dinner rolls. How much flour is needed to make 9 rolls?

From the above question, we know that:

27 dinner rolls = 3 cups of flour

9 dinner rolls = x

Cross Multiply

27 rolls × x = 9 rolls × 3 cups

x = 9 rolls × 3 cups/27 rolls

x = 1 cup of flour

Hence, 1 cup of flour is needed to make 9 dinner rolls

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From the above question:

4 km = 18 minutes

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Cross Multiply

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x = 15km × 18minutes/4km

x = 67.5 minutes

Hence, in a 15km race , it would take her 67.5 minutes to complete her race.

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