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vagabundo [1.1K]
3 years ago
15

Suma40grados 35 con60grados7erорq' wa' rty ua s d f g h j k l ñ en español​

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

Je ne sais pas sur quoi vous avez besoin d'aide, pourriez-vous préciser pour que je puisse vous aider ??

Step-by-step explanation:

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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that p = 0.26

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that n = 5

4 failures, so 1 success, and we have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.3898 = 38.98% probability that there will be 4 failures

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