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gladu [14]
3 years ago
8

6/9=x/6 solve for the variable x

Mathematics
1 answer:
sammy [17]3 years ago
6 0

\frac{6}{9}  =  \frac{x}{6} \Leftrightarrow x =  \frac{ {6}^{2} }{9}  =  \frac{36}{9}  = 4

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if a tv has a diagonal measurement of 55 and a height of 30, what is the tvs width? round to the nearest whole number
Sati [7]

Answer:

  46

Step-by-step explanation:

The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.

__

<h3>Pythagorean theorem</h3>

The relation between the leg lengths (a, b) and the hypotenuse (c) is ...

  c² = a² +b²

Solving for b gives ...

  b = √(c² -a²)

<h3>application</h3>

In this problem, we have c=55 and a=30. Then the width of the TV is ...

  b = √(55² -30²) = √(3025 -900) = √2125

  b ≈ 46.098

The width of the TV is about 46.

7 0
2 years ago
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Alex787 [66]
1/4 in fraction form, or 0.4 in decimal
5 0
3 years ago
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oksian1 [2.3K]

Given :-

  • a² - 2a - b² = 0
  • 2b + 2ab = 0

To find :-

  • Value of a and b .

Solution :-

<u>Taking</u><u> </u><u>second</u><u> </u><u>equation</u><u>:</u><u>-</u>

  • 2b + 2ab = 0
  • 2b ( 1 + a ) = 0
  • 2b = 0 or (1+a) = 0
  • b = 0 , a = -1

<u>Substitute</u><u> </u><u>in </u><u>first </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>

  • a² - 2a - b² = 0

<u>When </u><u>b </u><u>=</u><u> </u><u>0</u><u> </u><u>,</u>

  • a² - 2a - 0² = 0
  • a² - a = 0
  • a( a -1) =0
  • a = 0 , 1

<u>When </u><u>a </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>,</u>

  • (-1)² - 2*(-1) - b² = 0
  • 1 + 2 - b² = 0
  • b² = 3
  • b = ±√3

<u>Answer </u><u>:</u><u>-</u><u> </u>

  • a = 0,1 ; b = 0
  • a = -1 , b = ±√3
8 0
2 years ago
Betty's height to jinlan's height
ella [17]
1 to 2 m tall please forgive meh
8 0
3 years ago
25)
Liula [17]

Answer:

A) w=3

Step-by-step explanation:

4 x 3 = 12

This is the work when you plug in the numbers in the varible w

6 0
3 years ago
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