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Lady bird [3.3K]
3 years ago
15

What is 31.5% as a fraction (please help me with this one)

Mathematics
2 answers:
Simora [160]3 years ago
4 0

Answer:

63/2

Step-by-step explanation:

Katena32 [7]3 years ago
4 0

Answer:

63/200

Step-by-step explanation:

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Find the value of x.
Luden [163]

Answer:

Step-by-step explanation:

Remark

Since the chords of the circle are equal and non intersecting, The 2 bisecting perpendiculars are going to be equal.

Equation

5x = 7x - 8           Subtract 7x from both sides

5x - 7x = - 8

-2x = - 8              Divide by - 2

x = - 8/-2

x = 5

6 0
3 years ago
You park in a garage 3 floors below ground level. Then you get in the elevator and go up 12 floors. What floor do you get off th
Gemiola [76]

Answer: (B) 6 floors

Step-by-step explanation: Use the equation -3 + 9 to get the amount of floors above ground level.

-3 + 9 = 6

6 floors.

If this helps may I please have a brainliest.

5 0
3 years ago
Read 2 more answers
Find sin^4(a) + cos^4(a), if cos(a) + sin(a) = 1/3
Nadya [2.5K]

Answer:

49/81

Step-by-step explanation:

[cos(a) + sin(a)]^2 = (1/3)^2

(cos(a))^2 + 2sin(a)cos(a) + (sin(a))^2 = 1/9

(sin(a))^2 + (cos(a))^2 = 1

1 + 2sin(a)cos(a) = 1/9

2sin(a)cos(a) = -8/9

sin(a)cos(a) = -4/9

[cos(a) + sin(a)]^4 = (1/3)^4 = 1/81

(cos(a))^4 + 4sin(a)×(cos(a))^3 + 6×(sin(a))^2×(cos(a))^2 + 4(sin(a))^3×cos(a) + (sin(a))^4 = 1/81

(cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)((cos(a))^2 + (sin(a))^2) + 6(sin(a)cos(a))^2 = 1/81

cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)(1) + 6(sin(a)cos(a))^2 = 1/81

(cos(a))^4 + (sin(a))^4 + 4(-4/9) +6((-4/9)^2) = 1/81

(cos(a))^4 + (sin(a))^4 - 16/9 + 6(16/81) = 1/81

(cos(a))^4 + (sin(a))^4 = 1/81 + 16/9 - 6(16/81)

(cos(a))^4 + (sin(a))^4 = 49/81

3 0
3 years ago
A true/false test has 6 questions. If a student were to guess the answer to
Lorico [155]

Answer:

36 I think!

Step-by-step explanation:

7 0
3 years ago
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Please help me tysm!
Nikolay [14]

Answer:

Z.

Step-by-step explanation:

I wrote down the subject with the number of students. I looked one by one to see if the number of students with the subject matched with the graph.  Then I finally found that the last graph matched with what I written down.

7 0
3 years ago
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