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Gnesinka [82]
3 years ago
13

Akiko, manager of Little Ginza, is concerned about ordering the right amount of salmon. Daily consumption of salmon has a mean o

f 12 pounds and a standard deviation of 3.2 pounds.
a. Define the random variable and its probability distribution.
b. What is the probability the demand for salmon at Little Ginza between 4 and 8 pounds?
c. 97.5 percent of Little Ginza’s customers will demand between how many pounds of salmon on any given day?
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

Answer:

I believe the answer is a

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ioda

Answer:

im 12!! how do you do this

Step-by-step explanation:

3 0
3 years ago
He figure is rotated counterclockwise. Which rotation could have taken place?
ruslelena [56]

Answer:

a 90° rotation

I'm not sure about answer...

7 0
3 years ago
2 × 7/8 as a model how do I draw it as a model
White raven [17]
One way to do it is you can draw two sets of 7/8.


You can draw 8 tiles, and color in 7.

Draw that two times.

That’s one way, but that might not be the way you learned it.


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7 0
3 years ago
25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
3 years ago
PLEASE HELP MEEE OMG.. IDK WHAT THIS ANSWER COULD BE IVE TRYED L×W×H AND IDK WHAT IT COULD BE!!​
anzhelika [568]
I think it would be 17.5
3 0
3 years ago
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