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3 years ago

Warhol's early paintings of these objects made him famous.

Physics

2 answers:

shepuryov [24]3 years ago

8 0

Soup cans is the right answer.

Elena-2011 [213]3 years ago

5 0

Soup cans is the correct answer

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Describe the ratio of kinetic energy and potential energy the skateboarder will have at each of the following points in her ride

amm1812

Answer:

no answer

Explanation:

7 0

3 years ago

Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance

SSSSS [86.1K]

Answer:

${F_{tot} = -1.092*10^{-2}N$

Explanation:

The question: What is the net force exerted by these two charges on a third charge q_3 = 47.0 nC placed between q_1 and q_2 at x_3 = -1.240 mm ?

<u>Your answer may be positive or negative, depending on the direction of the force.</u>

Solution:

The coulomb force is given by the equation

$F =k\dfrac{q_1 q_2}{d^2}.$

where $d$ is the separation between the charges $q_1$ and $q_2$ .

Now, in our case

$q_1=-13.5nC=-13.5*10^{-9}C$

$q_2=-1.735nC=-1.735*10^{-9}C$

$q_3= 47*10^{-9}C$

The separation between charges $q_3$ and $q_1$ is

$d_{31}= (-1.240mm)-(-1.735mm)=0.495mm=4.95*10^{-4} m$

Therefore, the force between them is

$F_{31} = (9*10^9NmC^{-2})\dfrac{47*10^{-9}*(-13.5*10^{-9})}{4.95*10^{-4}} =-0.01152N$

and it is directed in the negative x-direction.

The separation between charges $q_2$ and $q_3$ is

$d_{23} =-1.240mm-0=-1.240*10^{-3}m$

therefore, the force between them is

$F_{23} =(9*10^9Nm^2C^{-2})\dfrac{47*10^{-9}C*(-1.735*10^{-9}C)}{-1.240*10^{-3}m}=5.94*10^{-4}N$

Therefore the total force on charge $q_3$ is

$F_{tot} =5.94*10^{-4}-0.01152N = -0.010926N\\\\\boxed{F_{tot} = -1.092*10^{-2}N}$

8 0

3 years ago

A mass on a spring oscillates with a period T. Part A If both the mass and the force constant of the spring are doubled, the new

garik1379 [7]

Answer:

The new time period will be T.

Explanation:

The time period in terms of spring constant and mass is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

If mass and force constant is doubled, m' = 2m and k' = 2k

New time period is given by :

$T'=2\pi\sqrt{\dfrac{m'}{k'}}$

$T'=2\pi\sqrt{\dfrac{2m}{2k}}$

$T'=2\pi\sqrt{\dfrac{m}{k}}$

$T'=T$

So, the new period will remains the same. Hence, the correct option is (C).

4 0

3 years ago

A student tosses a ball horizontally from a balcony to a friend 3.8 meters down below them. How long does the ball take to reach

Vsevolod [243]

Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due gravity of the ball = 9.81 m/s²

t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

∴ t = √0.775 ≈ 0.88 seconds

The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.

8 0

3 years ago

Lowest form of energy from the sun

Ugo [173]

UVA

I'm pretty sure it's UVA :)

8 0

3 years ago