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FromTheMoon [43]
3 years ago
14

Can someone help me please !!!!! Today is the last day and I don’t know anything help me please

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

C = 10

D = 5

Step-by-step explanation:

glad to help :D

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Fjfvbfsjbs;jf;bsfjmn km
N76 [4]

Answer:

gdvf ,;lcx ;

Step-by-step explanation:

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3 years ago
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If sin tetha=root3/2, what is cos tetha?​
Minchanka [31]

Answer:

The value of cos Ф is ± \frac{1}{2}

Step-by-step explanation:

There are important rules for sin Ф and cos Ф

  • sin²Ф + cos²Ф = 1
  • sin²Ф = 1 - cos²Ф
  • cos²Ф = 1 - sin²Ф

∵ sin Ф = \frac{\sqrt{3}}{2}

∴ sin²Ф = (\frac{\sqrt{3}}{2})^{2}

∴ sin²Ф = \frac{3}{4}

→ By using the third rule above

∵ cos²Ф = 1 - sin²Ф

∴ cos²Ф = 1 - \frac{3}{4}

∴ cos²Ф = \frac{1}{4}

→ Take square root for both sides

∴ cos Ф = ± \frac{1}{2}

∴ The value of cos Ф is ± \frac{1}{2}

6 0
3 years ago
If it's 11:51 right now. what time will not be in 11 hours and 37 minutes ?
AfilCa [17]

Answer:

11:52...

Step-by-step explanation:

11:52. It could be any time except the time 11:37 from now, since its NOT going to be.

Hope this helps!

6 0
3 years ago
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If the public debt of the United States in 2004 was $7,379,052,696,330.32 and the budget deficit in 2005 was $553,656,965,393.18
slava [35]
Since there is a shortage in the budget in 2005 by 553,656,965,393.18, the total debt that of the United States in 2005 will be the public debt by 2004 added with this deficit in the budget. Having said that, the public debt by 2004 should be equal to,
                       $ 7.9327 x 10^12
3 0
3 years ago
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The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba
Olegator [25]

Answer:

The probability that occurrence of 8 in ten minutes is 0.0771.

Step-by-step explanation:

Poisson Distribution:

A discrete random variable X having the enumerable set {0,1,2,.....} as the spectrum, is said to have Poisson distribution with parameter \mu (>0), if the p.m.f is given by

P(X=x)=\frac{e^{-mu}\mu^x}{x!}  for x=0,1,2,...

               = 0,           elsewhere

The mean number of occurrences in ten minutes is 5.3.

Here \mu = 5.3 and x= 8

P(X=8)=\frac{e^{-5.3}(5.3)^8}{8!}

               =0.0771

The probability that occurrence of 8 in ten minutes is 0.0771.

3 0
3 years ago
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