You should calculate( the area of a circle of radius 15 cm ) minus the area of the circle of radius (15 cm - width of the frame). I am not able to read the number, sorry.
That is the surface area of the frame.
Then, if area of circle radius is 100%, the % of face of the clock is:
(100xareaCircle(15cm-widthframe))/areaCircle15cm
Send a better photo or tell me what I’m suppose to be answering
Answer:
6ab(2a-3b-5b²)
Step-by-step explanation:
6(2a²b-3ab²-5ab³)
6a(2ab-3b²-5b³)
6ab(2a-3b-5b²)
