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3 years ago

8

a plumber worked at a house on two diffrent days. on the first day, the plumber worked for 5/8 of an hour, on the second day the

plumber worked for 1/4.What is the total amount of time, in hours , the plumber worked

1 answer:

Mademuasel [1]3 years ago

5 0

Answer: The plumber worked 7/8 hours in total.

Step-by-step explanation:

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The sum of two segments are 75 cm, and one the segments are four times the other. Calculate the measurement of each segment

iVinArrow [24]

The length of one segment is 15 cm and other segment is 60 cm

Step-by-step explanation:

Let x be the length of one segment and y be the length of other segment

Then according to given statement

x+y=75 Eqn 1

And

one the segments are four times the other

x=4y Eqn 2

$Putting\ x=4y\ in\ equation\ 1$

$4y+y=75\\5y=75\\Dividing\ both\ sides\ by\ 5\\\frac{5y}{5}=\frac{75}{5}\\y=15\\Putting\ y=15\ in\ eqn\ 2\\x=4(15)\\x=60$

Hence,

The length of one segment is 15 cm and other segment is 60 cm

Keywords: Linear Equation, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Marcy’s company produces grandfather clocks. Each clock costs them $164 to make, and they can sell a clock for $625. If their an

padilas [110]

Answer:

c.208

Step-by-step explanation:

In order to solve this you just have to calculate how much money can they make by selling one clock, so as you can see they sell the clock at $625, and the cost of producing that clock is $164, the profut for each clock is the selling price minus the cost of producing it:

625-164= 461

So now you just have to divide the annual overhead by the profit to see how many clock you need to sell to break even:

96,000/461= 208.24

So Marcy´s company need to sell 208 clocks in order to break even with profits and annual overheads.

3 0

4 years ago

Read 2 more answers

What is 4/3 divided by 5/3

Deffense [45]

4/5 because if you divide it would be 12/15 so I simplified

8 0

4 years ago

Read 2 more answers

Rationalise the equation :<br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%20%5E%7B2%7D%20%7D%7B%20%5Csqrt%7Bx%5E%7B2%7D

Nat2105 [25]

Answer:

$\sqrt{x^2+y^2}-x$

Step-by-step explanation:

$\textsf{Mulitply by}\quad\dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}:$

$\implies \dfrac{y^2}{\sqrt{x^2+y^2}+x} \times \dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2}+x)(\sqrt{x^2+y^2}-x)}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2})^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{x^2+y^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{y^2}$

$\textsf{Cancel the common factor}\:y^2:$

$\implies \sqrt{x^2+y^2}-x$

6 0

3 years ago

Read 2 more answers

What is the factored for of 6x^2+13x+6

spayn [35]

(3x + 2)(2x+3) that’s the factored version

3 0

3 years ago