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Zepler [3.9K]
3 years ago
15

Who likes cats? brainliest

Mathematics
2 answers:
Flauer [41]3 years ago
8 0

Answer:

ME

Step-by-step explanation:

hope this answer your question

ollegr [7]3 years ago
6 0

Answer:

Me

Step-by-step explanation:

You might be interested in
I need help with these questions (see image). Please show workings.<br>​
denpristay [2]

Answer:

24 cm

Step-by-step explanation:

The altitude from the centre to the chord is 5 cm and bisects the chord.

The radius of the circle is 26 cm ÷ 2 = 13 cm

There is a right triangle formed with legs 5 and x ( x is half the chord )

The hypotenuse is the radius, then using Pythagoras' identity

x² + 5² = 13²

x² + 25 = 169 ( subtract 25 from both sides )

x² = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

Then

length of chord = 2x = 2 × 12 = 24 cm

4 0
3 years ago
Read 2 more answers
In a class of 32 students 25% are boys. How many students are boys?
12345 [234]

Answer:

8

Step-by-step explanation:

0.25 * 32=8, meaning that 8 of the students are boys. 32 is the whole, because it is the entire class. Hope this helps!

6 0
3 years ago
Read 2 more answers
Solve for X, and show the equation you would use to solve.
Lady_Fox [76]

Opposite interior angles are equal, so

4x - 10 = 2x + 20

2x - 10 = 20

2x = 30

x = 15

6 0
3 years ago
Read 2 more answers
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
What are the next three terms of the geometric sequence 32, -16, 8, …?
MrRa [10]

Answer:

-4, 2, -1

Step-by-step explanation:

everything is being multiplied by -1/2

32 × -1/2 = -16

-16 × -1/2 = 8

So 8 × -1/2 = -4

8 0
3 years ago
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