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kirza4 [7]
4 years ago
8

Cu(s) + NO3- (aq) ---> Cu2+ (aq) + NO

Chemistry
1 answer:
lana66690 [7]4 years ago
8 0
Oxidation half reaction :- 

<span>Cu --------> Cu2+ + 2e- ...(1) </span>

<span>this is the balanced oxidation half reaction </span>

<span>b) reduction half reaction :- </span>

<span>NO3- -----------> NO </span>

<span>balance oxidation no. </span>

<span>NO3- + 3e- --------> NO </span>

<span>balance charge by adding H+ </span>

<span>NO3- + 3e- + 4H+ ---------> NO </span>

<span>now balance O and H atoms by addin H2O... </span>

<span>NO3- + 3e- + 4H+ ---------> NO + 2H2O....(2) </span>

<span>this is balanced reduction half reaction </span>

<span>multiply (1) by 3 and (2) by 2 and add </span>

<span>3Cu ---------> 3Cu2+ + 6e- </span>
<span>2NO3- + 6e- + 8H+ ---------> 2NO + 4H2O </span>
<span>--------------------------------------... </span>

<span>6e- will cancel out fom both sides... </span>

<span>3Cu + 2NO3- + 8H+ ---------> 3Cu2+ + 2NO + 4H2O </span>
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