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nata0808 [166]
3 years ago
6

Explain why Ra is larger than Be. With 2 points.

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
6 0

Explanation:

<h2>Radium(Ra)=> </h2>

atomic number=88

<h2>BERYLLIUM (Be)=></h2>

atomic number =4

why is Ra larger than Be

<h3>1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. </h3><h2>(atomic Radius)</h2>

<h2>2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction force</h2><h3>since Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.</h3>

hope it helps:)

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12. How many moles of atoms are present in 154 g of Na2O?
tia_tia [17]

Answer:

\boxed {\boxed {\sf A. \ 2.48 \ mol \ Na_2O}}

Explanation:

We are asked to convert an amount in grams to moles. To do this, we use the molar mass. This is the number of grams in one mole of a substance. It is the same value numerically as the atomic mass on the Periodic Table, however the units are grams per mole, not atomic mass units.

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Look back at the formula: Na₂O. Notice there is a subscript of 2 after sodium. This means there are 2 atoms of sodium in every molecule, so we have to multiply sodium's molar mass by 2 before adding oxygen's.

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Set up a ratio using the molar mass.

\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}

Multiply by the given number of grams.

154 \ g \ Na_2O*\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}

Flip the ratio so the grams of sodium oxide can cancel each other out.

154 \ g \ Na_2O*\frac {1  \ mol \ Na_2O}{61.9785386 \ g \ Na_2O}

154 *\frac {1  \ mol \ Na_2O}{61.9785386 }

\frac {154}{61.9785386 }  \ mol \ Na_2O

2.48473106141 \ mol \ Na_2O

The original measurement of grams given has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

  • 2.48<u>4</u>73106141

The 4 in the thousandth place tells us to leave the 8.

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There are <u>2.48 moles of sodium oxide</u> in 154 grams, so choice A is correct.

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