One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What
1 answer:
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Answer:
3, 7, 11, 15, 19, 23, 27,.......
Step-by-step explanation:
Let the first term and the common difference of the AP be a and d respectively.
Therefore,
a + (7- 1) d = 27
a + 6d = 27
a = 27 - 6d...... (1)
Therefore,
a + (12 - 1) d = 47
a + 11d = 47......(2)
From equations (1) & (2)
27 - 6d + 11d = 47
24 + 5d = 47
5d = 47 - 27
5d = 20
d = 20/5
d = 4
Plug d = 4 in equation (1) we find:
a = 27 - 6*4
a = 27 - 24
a = 3
Therefore,
Thus, the sequence is: 3, 7, 11, 15, 19, 23, 27,.......