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taurus [48]
2 years ago
11

The time (in number of days) until maturity of a certain variety of tomato plant is Normally distributed with mean μ. You select

a simple random sample of four plants of this variety and measure the time until maturity. The four times, in days, are as follows: 63 69 62 66 with standard deviation 3.16.
Required:
Calculate the 99% confidence interval for population mean μ. Find the closest answer
Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer: 60.93 < μ < 69.07

Step-by-step explanation: The true mean of a set of data is between an interval of values with a percentage of precision, e.g., a <u>99% confidence interval</u> means we are 99% confident the true mean is between the lower and upper limits.

To find the interval, use

x±z\frac{s}{\sqrt{n}}

z is z-score related to the % of confidence level

In this case, a 99% confidence interval is 2.576

x is sample mean

Calculating:

x=\frac{63+69+62+66}{4}

x = 65

65±2.576\frac{3.16}{\sqrt{4}}

65±4.07

Confidence Interval: 60.93 < μ < 69.07

Meaning that we are 99% sure the population means is between 60.93 and 69.07.

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galina1969 [7]

Answer:

17(maybe)

Step-by-step explanation:

12-(-5)=17

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3 years ago
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wel

Answer:

area equals 36 and 3 fourths because if you cut the triangle off of one of the sides and add it to the other side it makes a rectangle then you do length times width to find regular area of a rectangle.

7 0
3 years ago
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ELEN [110]

Answer:

The answer is A I hope it’s right

Step-by-step explanation:

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5 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Tony is trying to find the solution of the system 2x - 4y +12 using elimination 3x + 4y = 48 He wrote these steps to solve the p
kobusy [5.1K]

Answer: Solution: (12, 3)

Step-by-step explanation:

2x - 4y = 12

3x + 4y = 48

Add both equations

5x = 60

Divide both sides by 5

x = 12

We can use the value of x to find y

3x + 4y = 48

3 (12) + 4y = 48

36 + 4y = 48

Subtract 36 from both sides

4y = 12

Divide both sides by 4

y = 3

Solution: (12, 3)

7 0
3 years ago
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