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Wittaler [7]
2 years ago
14

The two circle graphs show how Rosalyn and Laura spent their last Saturday. In which activity did both Rosalyn and Laura spend 1

/4 of their time? A.
watching movies


B.
buying groceries


C.
running errands


D.
sleeping

Mathematics
2 answers:
trasher [3.6K]2 years ago
7 0

Answer:

Step-by-step explanation:

its sleeping. So 1/4 is 25%. And if you make a dollar out of qurters then you see each are 25. And 25 is 1 out of 4  to make a dollar, so your answer is sleeping/25%

hope it helps ;)

svlad2 [7]2 years ago
6 0
They both spent 1/4 if their time sleeping. As 1/4 is 25%
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Step-by-step explanation

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Answer:

Step-by-step explanation:

let  the first piece=x ft

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Find the range of the function.<br> f(x) = 10-x^2
BARSIC [14]
Answer:
range = x ≤ 10
Step-by-step explanation:
Given in the question the function
f(x)=10-x^2
The range of a function is the complete set of all possible resulting values of the dependent variable F(x) after we have substituted the domain which is the values of x.
domain = set of all integers
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7 0
2 years ago
PLS HELP!!! The figure below has a point marked with a large dot.
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7 0
3 years ago
A carpentry shop currently sells 66000 decoy ducks per year at a cost of 16 dollars each. In the previous year when they raised
Rus_ich [418]

Answer:

19 dollars

Step-by-step explanation:

<h2>Buckle up! This is a good one!</h2>

First we have to find the line that goes trough the two points. And it has the form :

y=mx+b

<em>m is often called the slope.</em>

Given the two points (66000, 16) and (51000, 21) we find m with this formula:

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\\m=\frac{21-16}{51000-66000} \\m=-\frac{5}{15000} \\m=-\frac{1}{3000}

We pick the point (51000,21) and plug it into the equation of the line and we find b:

y= mx + b\\21=(-\frac{1}{3000} )(51000)+b\\21=-17+b\\21+17=b=38

<h3>And we have got our line equation</h3>

y= -\frac{1}{3000}x + 38\\

<u>Where x represents the quantity and y represents the price.</u>

<u />

<h2>The revenue</h2>

The revenue is price times quantity, since price is y and quantity is x, we get

y=-\frac{1}{3000} x+38\\y*x=x*(-\frac{1}{3000} x+38)\\yx=-\frac{1}{3000} x^2+38x\\R(x)=-\frac{1}{3000} x^2+38x

<h3>to maximize the revenue, we get the first derivative:</h3>

R(x)=-\frac{1}{3000} x^2+38x\\R'(x)=-(2)\frac{1}{3000} x+38\\R'(x)=-\frac{2}{3000} x+38\\\\R'(x)=-\frac{1}{1500} x+38\\\\

<h3>and we make R'(x)=0:</h3>

R'(x)=-\frac{1}{1500} x+38=0\\38=\frac{1}{1500} x\\38*1500=x=57000

So the quantity that maximizes revenue is 57000,

<h3>let's find out the price by plugging it into the equation:</h3>

y= -\frac{1}{3000}x + 38\\y= -\frac{1}{3000}(57000) + 38\\y= -19 + 38\\y=19

<h2>And there you go! 19 dollars is the price the carpentry shop should charge per decoy duck.</h2>
7 0
3 years ago
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