There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Answer:
B.
Step-by-step explanation:
First, let's start from the parent function. The parent function is:

The possible transformations are so:
,
where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.
From the given equation, we can see that a=1 (so no change), b=3, c=-3 (<em>negative </em>3), and d=3.
Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the <em>left </em>(because it's negative), and a vertical shift of 3 upwards (because it's positive).
Answer:
Step-by-step explanation:
A_{n+1}=14*A_{n}
A_{1}=8
A_{1+1}=14×8=112
A_{2}=112
A_{3}=14*A_{2}=14×112=1568
A_{4}=14*A_{3}=14×1568=21952
A_{5}=14*A_{4}=14×21952=307328
Answer:
77.
Proved
78.
Proved
79.
Proved.
80.
Proved.
Step-by-step explanation:
77. Left hand side
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= Right hand side (Proved)
78. Left hand side
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= Right hand side (Proved)
79. Left hand side
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{Since
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= Right hand side
80. Left hand side
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{Since
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= Right hand side. (Proved)
$47.50
Step-by-step explanation:
Before tax proce is $72.29
sales tax is 9.5%= $6.87
$72.29+$6.87=$79.16
40% off of $79.16=$47.50